2014年9月11日星期四

C4040-121 Exam PDF, A2040-924 Test Answers, A2060-350 Real Exams

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C4040-121Exam Code: C4040-121
Exam Name: Virtualization Technical Support for IBM i -v1
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C4040-121 Bootcamp Total Q&A: 102 Questions and Answers
Last Update: 2014-09-11

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A2040-924Exam Code: A2040-924
Exam Name: Assessment: IBM WebSphere Portal 8.0 Migration and Support
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A2040-924 Exam Dumps Total Q&A: 68 Questions and Answers
Last Update: 2014-09-11

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A2060-350Exam Code: A2060-350
Exam Name: Assessment: IBM WebSphere Transformation Extender V8.4 Application Development
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A2060-350 Braindumps Total Q&A: 63 Questions and Answers
Last Update: 2014-09-11

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NO.1 What is the primary difference between a choice group and a partitioned group?
A. A choice group requires that data must be distinguishable; a partitioned group does not.
B. A partitioned group requires that data must be distinguishable; a choice group does not.
C. A choice group can have both items and groups as components; a partition group can only have
groups as subtypes.
D. A partitioned group can contain both items and groups as components; a choice group can only
contain groups as components.
Answer: C

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NO.2 The image here shows the components of a purchase order:
The application requires that the total number of items (TotalItems) in the Trailer Record equals the
sum of the quantity ordered (QtyOrdered) for each purchase order.
This verification can be performed by a component rule. Which component should have the
component rule?
A. TotalItems
B. QtyOrdered
C. Detail Record
D. Trailer Record
Answer: D

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NO.3 An application developer has a file which consists of fixed length records.
The first record is a header record followed by some number of detail records.
The number of detail records is expressed by a value found in the header record.
How does the developer define this type of data in WebSphere Transformation Extender?
A. Index the input based on the count in the header record.
B. Use a Map function to keep track of how many detail records there are.
C. Write a custom function to store the number of detail records in the map context.
D. Use a component rule to compare the current record to the value found in the header.
Answer: D

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NO.4 Which two of the following statements are TRUE of syntax items? Syntax items:
A. are limited to 10 bytes.
B. can only be defined as character data.
C. can be defined as character or binary data.
D. are used as separators between portions of data.
Answer: B,D

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NO.5 Refer to image shown here:
Which of the following statements is TRUE with regards to the type trees created using the XML
Schema Importer.
A. The trees were created with different schemas.
B. One tree was created using XSDL Hints and Xerces validation.
C. One tree was created using Classic validation and XSDL Hints.
D. One tree was created using Classic validation and the other using Xerces validation.D.One tree
was created using Classic validation and the other using Xerces validation.
Answer: B

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NO.6 The structure of the following file has been partially defined in a type tree:
~Smith~Robert~Programmer<NL> ~Doe~John~Manager<NL>
The properties of the types have not been completely defined.
Which of the following options defines the properties for the use of the tilde (~) character in the
sample file?
A. Define ~ as a floating component of the Record type.
B. Define ~ character as a prefix delimiter of the File type.
C. Define ~ character as a prefix delimiter of the Record type.
D. Define ~ character as the initiator and terminator of LastName and FirstName types and initiator
of Title type.
Answer: C

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NO.7 Which statement about syntax items is TRUE?
A. They must have a restriction list.
B. They have a maximum length of 1 byte.
C. The value must come from the input data.
D. They cannot be used as variable initiators.
Answer: A

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NO.8 Which two of the following statements are TRUE of a component rule? A component rule:
A. is used to create output.
B. is used for data validation.
C. can refer to any other component in the component list.
D. is always evaluated even if an optional component is not present in the data.
Answer: B,D

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